a)
(10x^2+7x+4):(2x+1) = 5x+1 R=3
-10x^2-5x
----------------
////////////2x+4
///////////-2x-1
//////////////3 reszta
(10x^2+7x+4):(2x+1) = 5x+1 reszta R=3, czyli
10x^2+7x+4):(2x+1) = 5x+1+\frac{3}{2x+1}
b)
(3x^4-8x^3+4x^2+2x-2):(x-2) =3x^3-2x^2+2 R = 2
-3x^4+6x^3
--------------
//////-2x^3-4x^2
///////////////////////2x - 2
///////////////////////2x + 4
reszta = 2
(3x^4-8x^3+4x^2+2x-2):(x-2) =3x^3-2x^2+2+\frac{2}{x-2}