Zadanie 6
a)
2^{-5}=(\frac{1}{2})^5=\frac{1}{32}
b)
(-12)^{-2}=(-\frac{1}{12})^2=(\frac{1}{12})^2=\frac{1}{144}
c)
(\frac{1}{3})^{-3}=3^3=27
d)
(-\frac{4}{5})^{-3}=(-\frac{5}{4})^3=-\frac{125}{64}=-1\frac{61}{64}
e)
(1\frac{1}{2})^{-5}=(\frac{3}{2})^{-5}=(\frac{2}{3})^5=\frac{32}{243}
f)
(1\frac{1}{5})^{-3}=(\frac{6}{5})^{-3}=(\frac{5}{6})^3=\frac{125}{216}
g)
(2\frac{1}{2})^{-4}=(\frac{5}{2})^{-4}=(\frac{2}{5})^4=\frac{16}{625}
h)
(-3\frac{3}{7})^{-2}=(-\frac{24}{7})^{-2}=(-\frac{7}{24})^2=(\frac{7}{24})^2=\frac{49}{576}
i)
0,1^{-6}=(\frac{1}{10})^{-6}=10^{-6}=0,000001
j)
0,01^{-3}=(\frac{1}{100})^{-3}=100^3=1000000
k)
1,5^{-2}=(\frac{15}{10})^{-2}=(\frac{3}{2})^2=\frac{9}{4}=2\frac{1}{4}=2,25
l)
(-1,2)^{-3}=(\frac{12}{10})^{-3}=(\frac{6}{5})^{-3}=(\frac{5}{6})^3=\frac{125}{216}