\sqrt{1\frac{13}{36}}*(-2)^2-1,1:2\frac{1}{5}
źródło:
\sqrt{1\frac{13}{36}}*(-2)^2-1,1:2\frac{1}{5}=
=\sqrt{\frac{49}{36}}*4-\frac{11}{10}:\frac{11}{5}=\frac{7}{6}*4-\frac{11*5}{10*11}=
=\frac{14}{3}-\frac{1}{2}=\frac{28}{6}-\frac{3}{6}=\frac{25}{6}=4\frac{1}{6}